Theorem Proving in Lean

Kirby Linvill

Thursday, October 16, 2025

\(\newcommand{\TirName}[1]{\text{#1}} \newcommand{\inferlab}[3]{ \let\and\qquad \begin{array}{l} \TirName{#1} \\ \displaystyle \frac{#2}{#3} \end{array} } \newcommand{\inferright}[3]{ \let\and\qquad \displaystyle \frac{#2}{#3}\TirName{#1} } \newcommand{\inferrule}[3][]{\inferlab{#1}{#2}{#3}} \newcommand{\infer}[3][]{\inferrule[#1]{#2}{#3}} \)